\(3\left|2x+1\right|=x-2\quad\left(1\right)\)
TH1: \(x\ge-\dfrac{1}{2},\quad\left(1\right)\Leftrightarrow3\left(2x+1\right)=x-2\Leftrightarrow x=-1\left(\text{loại}\right)\)
TH2: \(x< -\dfrac{1}{2},\quad\left(1\right)\Leftrightarrow-3\left(2x+1\right)=x-2\Leftrightarrow-7x=1\Leftrightarrow x=-\dfrac{1}{7}\left(\text{loại}\right)\)
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